Question

Answer 1

a) $Zn + H_2SO_4 \to ZnSO_4 + H_2$
$n_{Zn} = n_{H_2} = \dfrac{4,48}{22,4} = 0,2(mol)$
$m_{Zn} = 0,2.65 = 13(gam)$
b) $n_{H_2SO_4} = n_{H_2} = 0,2(mol)$
$m_{H_2SO_4} = 0,2.98 = 19,6(gam)$
c) $n_{ZnSO_4} = n_{H_2} = 0,2(mol)$
$m_{ZnSO_4} = 0,2.161 = 32,2(gam)$