\(Bài1\)
\(a.\dfrac{-3}{7}\cdot\dfrac{6}{13}+\dfrac{-4}{7}\cdot\dfrac{6}{13}+\dfrac{-7}{13}=-\dfrac{18}{91}-\dfrac{24}{91}-\dfrac{7}{13}\)
\(=\dfrac{-42}{91}-\dfrac{7}{13}=-\dfrac{6}{13}-\dfrac{7}{13}=\dfrac{-13}{13}=-1.\)
\(b.\dfrac{7}{8}+\dfrac{13}{16}:26-\dfrac{6}{24}\cdot\left(-2\right)^3=\dfrac{7}{8}+\dfrac{13}{16}:26-\dfrac{1}{4}\cdot\left(-8\right)\)
\(=\dfrac{7}{8}+\dfrac{1}{32}-\left(-2\right)=\dfrac{93}{32}=2\dfrac{29}{32}.\)
\(c.\dfrac{12\cdot3\cdot\left(-4\right)\cdot5\cdot36}{100\cdot54}=\dfrac{-12\cdot3\cdot4\cdot5\cdot36}{100\cdot3\cdot18}=\dfrac{-12\cdot4\cdot5\cdot36}{4\cdot25\cdot18}\)
\(=\dfrac{-12\cdot5\cdot36}{25\cdot18}=\dfrac{-12\cdot5\cdot18\cdot2}{5\cdot5\cdot18}=\dfrac{-12\cdot2}{5}=-\dfrac{24}{5}.\)
\(d.\dfrac{27}{60}-\dfrac{15}{120}+9\dfrac{3}{10}-\dfrac{33}{24}=\dfrac{27}{60}-\dfrac{15}{120}+\dfrac{93}{10}-\dfrac{33}{24}\)
\(=\dfrac{9}{20}-\dfrac{1}{8}+\dfrac{93}{10}-\dfrac{11}{8}=\dfrac{9}{20}+\dfrac{-12}{8}+\dfrac{93}{10}=\dfrac{9}{20}-\dfrac{3}{2}+\dfrac{93}{10}\)
\(=\dfrac{9}{20}-\dfrac{30}{20}+\dfrac{196}{20}=\dfrac{165}{20}=\dfrac{33}{4}=8\dfrac{1}{4}.\)
