a) \(n_{H_2O}=\dfrac{72,15-44,07}{18}=1,56\left(mol\right)\)
=> \(n_{KCl.MgCl_2.xH_2O}=\dfrac{1,56}{x}\left(mol\right)\)
=> \(M_{KCl.MgCl_2.xH_2O}=\dfrac{72,15}{\dfrac{1,56}{x}}=46,25x\left(g/mol\right)\)
=> x = 6
b) \(n_{KCl.MgCl_2.6H_2O}=\dfrac{14,43}{277,5}=0,052\left(mol\right)\)
=> nCl = 0,052.3 = 0,156 (mol)
=> Số nguyên tử Cl = 0,156.6.1023 = 0,936.1023 (nguyên tử)