a, Ta có: \(n_{H_2}=0,4\left(mol\right)\)
PT: \(Mg+2HCl\rightarrow MgCl_2+H_2\)
___0,4____0,8____________0,4 (mol)
\(\Rightarrow m_{Mg}=0,4.24=9,6\left(g\right)\)
\(\Rightarrow\left\{{}\begin{matrix}\%m_{Mg}=\dfrac{9,6}{10}.100\%=96\%\\\%m_{Cu}=4\%\end{matrix}\right.\)
b, \(C_{M_{HCl}}=\dfrac{0,8}{0,5}=1,6\left(M\right)\)
c, Nửa hỗn hợp trên gồm 0,2 mol Mg và 0,003125 mol Cu.
PT: \(Mg+2H_2SO_{4\left(đ\right)}\underrightarrow{t^o}MgSO_4+SO_2+2H_2O\)
___0,2______________________0,2 (mol)
\(Cu+2H_2SO_{4\left(đ\right)}\underrightarrow{t^o}CuSO_4+SO_2+2H_2O\)
0,003125______________0,003125 (mol)
\(\Rightarrow V_{SO_2}=\left(0,2+0,003125\right).22,4=4,55\left(l\right)\)
Bạn tham khảo nhé!
