a) \(n_{Al_2\left(SO_4\right)_3}=0,5.0,2=0,1\left(mol\right)\)
\(n_{Ba\left(OH\right)_2}=0,8.0,4=0,32\left(mol\right)\)
PTHH: \(Al_2\left(SO_4\right)_3+3Ba\left(OH\right)_2\rightarrow3BaSO_4\downarrow+2Al\left(OH\right)_3\downarrow\)
0,1----------->0,3------------>0,3--------->0,2
\(2Al\left(OH\right)_3+Ba\left(OH\right)_2\rightarrow Ba\left(AlO_2\right)_2+4H_2O\)
0,04<-------0,02
Kết tủa gồm \(\left\{{}\begin{matrix}BaSO_4:0,3\left(mol\right)\\Al\left(OH\right)_3:0,16\left(mol\right)\end{matrix}\right.\)
=> mkt = 0,3.233 + 0,16.78 = 82,38 (g)
c)
\(\left\{{}\begin{matrix}n_{AlCl_3}=1.0,1=0,1\left(mol\right)\\n_{KOH}=1.0,5=0,5\left(mol\right)\end{matrix}\right.\)
PTHH: \(3KOH+AlCl_3\rightarrow Al\left(OH\right)_3\downarrow+3KCl\)
0,3<-----0,1-------->0,1
\(KOH+Al\left(OH\right)_3\rightarrow KAlO_2+2H_2O\)
0,1<------0,1
=> Không có kết tủa
d)
\(\left\{{}\begin{matrix}n_{NaAlO_2}=0,25.2=0,5\left(mol\right)\\n_{H_2SO_4}=2.0,375=0,75\left(mol\right)\end{matrix}\right.\)
PTHH: \(2NaAlO_2+H_2SO_4+2H_2O\rightarrow Na_2SO_4+2Al\left(OH\right)_3\downarrow\)
0,5------->0,25------------------------------->0,5
\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)
\(\dfrac{1}{3}\)<--------0,5
=> \(m_{Al\left(OH\right)_3}=\left(0,5-\dfrac{1}{3}\right).78=13\left(g\right)\)
e) \(\left\{{}\begin{matrix}n_{H_2SO_4}=0,6.0,5=0,3\left(mol\right)\\n_{K_2ZnO_2}=1.0,5=0,5\left(mol\right)\end{matrix}\right.\)
PTHH: \(K_2ZnO_2+H_2SO_4\rightarrow K_2SO_4+Zn\left(OH\right)_2\downarrow\)
0,3-------------------->0,3
=> \(m_{Zn\left(OH\right)_2}=0,3.99=29,7\left(g\right)\)
