Question

Answer 1

\(\lim\limits_{x\rightarrow-2^-}\dfrac{x^2-x-6}{\left|x+2\right|}=\lim\limits_{x\rightarrow-2^-}\dfrac{\left(x-3\right)\left(x+2\right)}{\left|x+2\right|}\)

Vì \(x\rightarrow-2^-\Rightarrow x+2< 0\)  \(\Rightarrow\left|x+2\right|=-\left(x+2\right)\)

Khi đó : \(\lim\limits_{x\rightarrow-2^-}\dfrac{\left(x-3\right)\left(x+2\right)}{-\left(x+2\right)}=\lim\limits_{x\rightarrow-2^-}3-x=3-\left(-2\right)=5\)

Chọn D 

Answer 2

gãy cổ