\(n_{H_2}=\dfrac{1,12}{22,4}=0,05\left(mol\right)\)
PTHH:
Mg + H2SO4 ---> MgSO4 + H2
Mg + 2HCl ---> MgCl2 + H2
Zn + H2SO4 ---> ZnSO4 + H2
Zn + 2HCl ---> ZnCl2 + H2
Theo pthh: \(n_{Mg}=n_{Zn}=n_{HCl}=n_{H_2SO_4}=n_{H_2}=0,05\left(mol\right)\)
\(\rightarrow\left\{{}\begin{matrix}\left\{{}\begin{matrix}m_{Mg}=0,05.24=1,2\left(g\right)\\m_{Zn}=0,05.65=3,25\left(g\right)\end{matrix}\right.\\\left\{{}\begin{matrix}m_{HCl}=0,05.36,5=1,925\left(g\right)\\m_{H_2SO_4}=0,05.98=4,9\left(g\right)\end{matrix}\right.\end{matrix}\right.\\ \rightarrow\left\{{}\begin{matrix}m_{Mg}< m_{Zn}\\m_{HCl}< m_{H_2SO_4}\end{matrix}\right.\)
Vậy chọn Mg và HCl
