a, PTHH:
2Mg + O2 --to--> 2MgO
4Al + 3O2 --to--> 2Al2O3
3Fe + 2O2 --to--> Fe3O4
b, Bảo toàn khối lượng:
\(m_{O_2}=m_{oxit}-m_{kl}=29,25-19,65=9,6\left(g\right)\\ \rightarrow n_{O_2}=\dfrac{9,6}{32}=0,3\left(mol\right)\\ \rightarrow V_{O_2}=0,3.22,4=6,72\left(l\right)\)