Question

Answer 1

\(\dfrac{1}{6}+\dfrac{5}{6}\left(\dfrac{1}{4}-\dfrac{2}{3}\right).\left(-3\right)^2+\dfrac{9}{20}\\ =\dfrac{1}{6}+\dfrac{5}{6}\left(-\dfrac{5}{12}\right).9+\dfrac{9}{20}\\ =\dfrac{1}{6}+\left(-\dfrac{25}{8}\right)+\dfrac{9}{20}\\ =\dfrac{-301}{120}\)

Answer 2

\(bàilàm:\dfrac{1}{6}+\dfrac{5}{6}.\left(\dfrac{1}{4}-\dfrac{2}{3}\right).\dfrac{-6}{1}+\dfrac{9}{20}=\dfrac{1}{6}+\dfrac{5}{6}.\dfrac{-5}{12}.\dfrac{-6}{1}+\dfrac{9}{20}=\dfrac{1}{6}+\dfrac{25}{12}+\dfrac{9}{20}=\dfrac{10}{60}+\dfrac{125}{60}+\dfrac{27}{60}=\dfrac{162}{60}=\dfrac{27}{10}\)