Question

Answer 1

\(\dfrac{x-5}{6}=\dfrac{x+1}{3}\\ \Rightarrow\dfrac{x-5}{6}=\dfrac{2\left(x+1\right)}{6}\\ \Rightarrow x-5=2\left(x+1\right)\\ \Rightarrow x-5=2x+2\\ \Rightarrow2x+2-x+5=0\\ \Rightarrow x+7=0\\ \Rightarrow x=-7\)

Answer 2

\(\dfrac{x-5}{6}=\dfrac{x+1}{3}\) \(\Leftrightarrow\) 3x-15=6x+6 \(\Leftrightarrow\) -3x=21 \(\Leftrightarrow\) x=-7.

Answer 3

<=>\(\dfrac{x-5}{6}\)=\(\dfrac{2x+2}{6}\)

<=>x-5=2x+2

<=>2x+x=-5+2

<=>3x=3

<=>x=1