\(\dfrac{x-1}{3}=\dfrac{-2}{5}\\ \Rightarrow5\left(x-1\right)=-2.3\\ \Rightarrow5x-5=-6\\ \Rightarrow5x=-6+5\\ \Rightarrow5x=-1\\ \Rightarrow x=-\dfrac{1}{5}\)
c) \(\dfrac{x-1}{3}=\dfrac{-2}{5}\)
\(\Leftrightarrow5\left(x-1\right)=\left(-2\right).3\)
\(\Leftrightarrow5x-5=-6\)
\(\Leftrightarrow5x+1=0\)
\(\Leftrightarrow x=\dfrac{-1}{5}\)
Vậy \(x=\dfrac{-1}{5}\)