a) \(\Delta H_{pư}=\left(-267\right)-4.\left(-57,8\right)=-35,8\left(kcal/mol\right)< 0\)
=> pư tỏa nhiệt
b) \(\Delta S_{pư}=3,5+32,21.4-6,49.3-45,1.4=-67,53\left(cal/mol.K\right)\)
\(\Delta G_{pư}=-35,8.10^3-298.\left(-67,53\right)=-15676,06\left(cal/mol\right)< 0\)
=> Pư tự diễn biến
Chọn C