Bài 2 :
`a)` \(\left(\dfrac{2}{3}x\dfrac{4}{5}\right)x\dfrac{5}{6}=\dfrac{2}{3}x\left(\dfrac{4}{5}x\dfrac{5}{6}\right)=\dfrac{2}{3}x\dfrac{4}{6}=\dfrac{8}{18}=\dfrac{4}{9}\)
`b)`\(\dfrac{19}{29}+\dfrac{9}{7}+\dfrac{7}{29}+\dfrac{12}{7}+\dfrac{3}{29}=\left(\dfrac{19}{29}+\dfrac{7}{29}+\dfrac{3}{29}\right)+\left(\dfrac{9}{7}+\dfrac{12}{7}\right)=\dfrac{29}{29}+\dfrac{21}{7}=1+3=4\)
