Question

Answer 1

giúp mình vs mn ơi

Answer 2

Bài 2: 

a: \(=6+\dfrac{4}{9}+3+\dfrac{7}{11}-4-\dfrac{4}{9}=5+\dfrac{7}{11}=\dfrac{62}{11}\)

b: \(=\dfrac{-4}{3}-\dfrac{17}{6}\cdot\dfrac{6}{11}+3:\dfrac{1}{20}\)

=-4/3-17/11+60

=1885/33

c: \(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{97}-\dfrac{1}{99}=\dfrac{1}{3}-\dfrac{1}{99}=\dfrac{32}{99}\)