Question

Answer 1

\(a=\dfrac{9}{10}+5=5\dfrac{9}{10};b,=\dfrac{20}{24}-\dfrac{12}{24}=\dfrac{8}{24}=\dfrac{1}{3}\\ c,=\dfrac{16}{9};d,=\dfrac{9\times4}{12\times3}=\dfrac{3}{3}=1\)

Answer 2

\(\dfrac{18}{20}+5=\dfrac{18}{20}+\dfrac{100}{20}=\dfrac{118}{20}\)

\(\dfrac{5}{6}-\dfrac{4}{8}=\dfrac{20}{24}-\dfrac{12}{24}=\dfrac{1}{3}\)

\(\dfrac{2}{9}\text{×}8=\dfrac{16}{9}\)

\(\dfrac{9}{12}:\dfrac{3}{4}=\dfrac{9}{12}\text{×}\dfrac{4}{3}=\dfrac{3}{3}=1\)