\(\dfrac{3.\left(x-2\right)}{6}+\dfrac{2.\left(x-2\right)}{6}+\dfrac{x-2}{6}=\dfrac{12}{6}\)
\(\Leftrightarrow3x-6+2x-4+x-2=12\)
\(\Leftrightarrow6x-12=12\)
\(\Leftrightarrow6x=12+12=24\\ \Leftrightarrow x=\dfrac{24}{6}=4\)
Vậy x = 4
\(\dfrac{6x-12}{12}+\dfrac{4x-8}{12}+\dfrac{2x-4}{12}=\dfrac{12}{12}\)
\(\Leftrightarrow6x-12+4x-8+2x-4=12\)
\(\Leftrightarrow12x-24=12\)
\(\Leftrightarrow x-2=1\)
\(\Leftrightarrow x=3\)

4 và 5