Question

Answer 1

\(a,M_{Na_2CO_3}=23.2+12+16.3=106\left(\dfrac{g}{mol}\right)\\ M_{Al\left(OH\right)_3}=27+\left(16+1\right).3=78\left(\dfrac{g}{mol}\right)\)

\(b,M_{K_3PO_4}=39.3+31+16.4=212\left(\dfrac{g}{mol}\right)\)

\(c,Fe_2\left(HPO_4\right)_3=56.2+\left(1+31+16.4\right).3=400\left(\dfrac{g}{mol}\right)\)

Answer 2

a) 106 g/mol

b) 78 g/mol

c) 212 g/mol

d) 400 g/mol