a) \(\left\{{}\begin{matrix}\%S=\dfrac{1.32}{80}.100\%=40\%\\\%O=\dfrac{3.16}{80}.100\%=60\%\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\%Na=\dfrac{23.1}{84}.100\%=27,381\%\\\%H=\dfrac{1.1}{84}.100\%=1,19\%\\\%C=\dfrac{12.1}{84}.100\%=14,286\%;\%O=\dfrac{16.3}{84}.100\%=57,143\%\end{matrix}\right.\)