Có: VC3H8 = VCH4 = 0,5(l)
=> \(\left\{{}\begin{matrix}n_{C_3H_8}=\dfrac{0,5}{22,4}=\dfrac{5}{224}\left(mol\right)\\n_{CH_4}=\dfrac{0,5}{22,4}=\dfrac{5}{224}\left(mol\right)\end{matrix}\right.\)
=> \(m_{hh}=\dfrac{5}{224}.44+\dfrac{5}{224}.16\approx1,339\left(g\right)\)