\(n_{Na_2CO_3}=\dfrac{10,6}{106}=0,1\left(mol\right)\\ PTHH:Na_2CO_3+2HCl\rightarrow2NaCl+H_2O+CO_2\uparrow\\ \Rightarrow n_{HCl}=2n_{Na_2CO_3}=0,2\left(mol\right)\\ \Rightarrow m_{CT_{HCl}}=0,2\cdot36,5=7,3\left(g\right)\\ \Rightarrow C\%_{HCl}=\dfrac{7,3}{200}\cdot100\%=3,65\%\)
Chọn A