\(PTHH:A+O_2\overset{t^o}{--->}CO_2+H_2O\)
Ta có: \(m_{O_{\left(CO_2\right)}}=\dfrac{8,8}{44}.16.2=6,4\left(g\right)\)
\(m_{O_{\left(H_2O\right)}}=\dfrac{1,8}{18}.16=1,6\left(g\right)\)
Ta thấy: \(3,2< 6,4+1,6\)
Vậy trong A có: \(\left\{{}\begin{matrix}C\\H\\O\end{matrix}\right.\)
Gọi CTHH của A là: CxHyOz
Ta có: \(m_{O_{\left(A\right)}}=6,4+1,6-3,2=4,8\left(g\right)\)
\(m_{C_{\left(A\right)}}=m_{C_{\left(CO_2\right)}}=\dfrac{8,8}{44}.12=2,4\left(g\right)\)
\(m_{H_{\left(A\right)}}=m_{H_{\left(H_2O\right)}}=\dfrac{1,8}{18}.1.2=0,2\left(g\right)\)
\(\Rightarrow x:y:z=\dfrac{4,8}{16}:\dfrac{2,4}{12}:\dfrac{0,2}{1}=0,3:0,2:0,2=3:2:2\)
Vậy CTHH của A là: \(C_3H_2O_2\)
