\(b,B=\sqrt{\left(2-\sqrt{3}\right)^2}+\dfrac{2+\sqrt{3}}{1}\\ B=2-\sqrt{3}+2+\sqrt{3}=4\\ 2,\\ a,A=4\sqrt{3}-12\sqrt{3}+20\sqrt{3}=12\sqrt{3}\\ b,B=\dfrac{\sqrt{3}\left(\sqrt{3}-2\right)}{\sqrt{3}}+\dfrac{6\left(3-\sqrt{3}\right)}{6}\\ B=\sqrt{3}-2+3-\sqrt{3}=1\)
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