a) \(n_{H_2}=\dfrac{1,12}{22,4}=0,05\left(mol\right)\)
PTHH: Zn + 2HCl → ZnCl2 + H2
Mol: 0,05 0,05 0,05
PTHH: ZnO + 2HCl → ZnCl2 + H2O
Mol:
b) \(m_{Zn}=0,05.65=3,25\left(g\right)\)
\(m_{ZnO}=5,675-3,25=2,425\left(g\right)\)
c) \(\%m_{Zn}=\dfrac{3,25.100\%}{5,675}=57,27\%\)
\(\%m_{ZnO}=100-57,27=42,78\%\)
d) \(n_{ZnCl_2}=0,05+\dfrac{2,425}{81}=0,12932\left(mol\right)\)
\(m_{ZnCl_2}=0,12932.136=17,58752\left(g\right)\)
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