Question

Answer 1

6.5/

a/ \(n_{Zn}=\dfrac{13}{65}=0,2\left(mol\right)\)

PTHH: Zn + 2HCl → ZnCl₂ + H₂

Mol:     0,2      0,4        0,2       0,2

\(V_{H_2}=0,2.22,4=4,48\left(l\right)\)

b/ \(m_{HCl}=0,4.36,5=14,6\left(g\right)\)

c/ \(C_{M_{ddZnCl_2}}=\dfrac{0,2}{0,2}=1M\)

Answer 2

6.6/

a/ \(n_{HCl}=0,4.0,3=0,12\left(mol\right)\)

PTHH: 2Al + 6HCl → 2AlCl₃ + 3H₂

Mol:     0,04      0,12      0,04 

,\(m_{Al}=0,04.27=1,08\left(g\right)\)

b, \(m_{AlCl_3}=0,04.133,5=5,34\left(g\right)\)

c, \(C_{M_{ddAlCl_3}}=\dfrac{0,04}{0,4}=0,1M\)