Bài 6:
\(a.n_{CO_2}=\dfrac{15,12}{22,4}=0,675\left(mol\right)\\ n_{Cl_2}=\dfrac{28,4}{71}=0,4\left(mol\right)\\ n_{H_2S}=\dfrac{7,28}{22,4}=0,35\left(mol\right)\\ n_{HNO_3}=\dfrac{15,75}{63}=0,25\left(mol\right)\\ b.m_{N_2O}=44.0,5=22\left(g\right)\\ m_{MgSO_4}=0,5.120=60\left(g\right)\\ m_{CaCO_3}=100.0,15=15\left(g\right)\\ m_{Fe_3O_4}=232.2=464\left(g\right)\\ m_{SO_2}=\dfrac{28}{22,4}.64=80\left(g\right)\)
\(c.V_{Cl_2}=\dfrac{31,95}{71}.22,4=10,08\left(l\right)\)
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