Question

Answer 1

a: \(8x^3-64=8\left(x^3-8\right)=8\left(x-2\right)\left(x^2+2x+4\right)\)

c: \(125x^3+1=\left(5x+1\right)\left(25x^2-5x+1\right)\)

d: \(8x^3-27=\left(2x-3\right)\left(4x^2+6x+9\right)\)

Answer 2

Ae bt cái này ko: a³ - b³ = ? , Mik chưa hc cái này nên chưa giải dc, mn chỉ mik với rồi mik giải cho nha.

Answer 3

a. 8x³ - 64

<=> (2x)³ - 4³

<=> (2x - 4)\(\left[\left(2x\right)^2+8x+16\right]\)

b. 1 + 8x⁶y³

<=> 1³ + (2x²y)³

<=> (1 + 2x²y)\(\left[\left(2x^2y\right)^2-2x^2y+1\right]\)

c. 125x³ + 1

<=> (5x)³ + 1³

<=> (5x + 1)\(\left[\left(5x\right)^2-5x+1\right]\)

d. 8x³ - 27

<=> (2x)³ - 3³

<=> (2x - 3)\(\left[\left(2x\right)^2+6x+9\right]\)

e. \(27x^3+\dfrac{y^3}{8}\)

<=> (3x)³ + \(\left(\dfrac{y}{2}\right)^3\)

<=> \(\left(3x+\dfrac{y}{2}\right)\left[\left(3x\right)^2-\dfrac{3xy}{2}+\dfrac{y^2}{4}\right]\)

f. 125x³ + 27y³

<=> (5x)³ + (3y)³

<=> (5x + 3y)\(\left[\left(5x\right)^2-5x.3y+\left(3y\right)^2\right]\)

Answer 4

b: \(8x^6y^3+1=\left(2x^2y+1\right)\left(4x^4y^2-2x^2y+1\right)\)

e: \(27x^3+\dfrac{1}{8}y^3=\left(3x+\dfrac{1}{2}y\right)\left(9x^2-\dfrac{3}{2}xy+\dfrac{1}{4}y^2\right)\)

f: \(125x^3+27y^3=\left(5x+3y\right)\left(25x^2-15xy+9y^2\right)\)