Câu 13 :
\(n_{SO_3}=\dfrac{8}{80}=0.1\left(mol\right)\)
\(SO_3+H_2O\rightarrow H_2SO_4\)
\(0.1........................0.1\)
\(C_{M_{H_2SO_4}}=\dfrac{0.1}{0.25}=0.4\left(M\right)\)
Câu 12 :
\(m_{CaCO_3}=80\%\cdot1=0.8\left(tấn\right)=800\left(kg\right)\)
\(n_{CaCO_3\left(pư\right)}=\dfrac{800\cdot85\%}{100}=6.8\left(kmol\right)\)
\(CaCO_3\underrightarrow{^{^{^{t^0}}}}CaO+CO_2\)
\(6.8...........6.8\)
\(m_{CaO}=6.8\cdot56=380.8\left(kg\right)\)
Câu 10 :
\(CT:MO\)
\(MO+H_2O\rightarrow M\left(OH\right)_2\)
\(\dfrac{15.3}{M+16}..........\dfrac{15.3}{M+16}\)
\(m_{M\left(OH\right)_2}=\dfrac{15.3}{M+16}\cdot\left(M+34\right)\left(g\right)\)
\(C\%M\left(OH\right)_2=\dfrac{\dfrac{15.3\cdot\left(M+34\right)}{M+16}}{200}\cdot100\%=8.55\%\)
\(\Rightarrow M=137\)
\(BaO\)
Câu 11 :
\(CT:XO_2\)
\(XO_2+H_2O\rightarrow H_2XO_3\)
\(\dfrac{38.4}{X+32}...............\dfrac{38.4}{X+32}\)
\(2NaOH+H_2XO_3\rightarrow Na_2XO_3+H_2O\)
\(..........\dfrac{38.4}{X+32}.......\dfrac{38.4}{X+32}\)
\(C\%_{Na_2XO_3}=\dfrac{\dfrac{38.4}{X+32}\cdot\left(X+94\right)}{400}\cdot100\%=18.9\%\)
\(\Rightarrow X=32\)
\(SO_2\)
