\(\Delta'=\left(m-4\right)^2-\left(m^2+4\right)=12-4m\ge0\Rightarrow m\le3\)
\(\left\{{}\begin{matrix}x_1+x_2=2\left(m-4\right)\\x_1x_2=m^2+4>0;\forall m\end{matrix}\right.\)
\(\frac{1}{x_1}+\frac{1}{x_2}+\frac{4}{x_1x_2}=1\Leftrightarrow\frac{x_1+x_2+4}{x_1x_2}=1\)
\(\Leftrightarrow x_1+x_2+4=x_1x_2\)
\(\Leftrightarrow2\left(m-4\right)+4=m^2+4\)
\(\Leftrightarrow m^2-2m+8=0\left(vn\right)\)
Vậy ko tồn tại m thỏa mãn yêu cầu