Question

 

\(\left|\frac{3}{x}.x+\frac{1}{2}\right|=\left|4\text{x}-1\right|\)

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Answer 1

x=\(\frac{-5}{8}\)

Answer 2

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Answer 3

\(\left|\frac{3}{x}.x+\frac{1}{2}\right|=\left|4x-1\right|\)

\(\Rightarrow\left|3+\frac{1}{2}\right|=\left|4x-1\right|\)

\(\Rightarrow\left|\frac{7}{2}\right|=\left|4x-1\right|\)

\(\Rightarrow\left|4x-1\right|=\frac{7}{2}=\frac{-7}{2}\)

\(\Rightarrow\orbr{\begin{cases}4x-1=\frac{7}{2}\\4x-1=\frac{-7}{2}\end{cases}}\Rightarrow\orbr{\begin{cases}4x=\frac{9}{2}\\4x=\frac{-5}{2}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{9}{8}\\x=\frac{-5}{8}\end{cases}}\)

Vậy \(x\in\left\{\frac{9}{8},\frac{-5}{8}\right\}\)

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Answer 4

X =-5/8