\(\sqrt{7-\sqrt{24}}=\sqrt{7-\sqrt{4.6}}=\sqrt{7-2\sqrt{6}}=\sqrt{6-2\sqrt{6}.1+1}=\sqrt{\left(\sqrt{6}-1\right)^2}=\left|\sqrt{6}-1\right|=\sqrt{6}-1\)
\(\sqrt{7-\sqrt{24}}=\sqrt{7-\sqrt{4.6}}=\sqrt{7-2\sqrt{6}}=\sqrt{6-2\sqrt{6}.1+1}=\sqrt{\left(\sqrt{6}-1\right)^2}=\left|\sqrt{6}-1\right|=\sqrt{6}-1\)
Tính giá trị các biểu thức sau:
a. \(\sqrt{2-\sqrt{3}}.\left(\sqrt{6}+\sqrt{2}\right)\)
b. \(\left(\sqrt{21}+7\right).\sqrt{10-2\sqrt{21}}\)
Giải phương trình:
1. \(\sqrt{36x-6}-\sqrt{9x-9}-\sqrt{4x-4}=16-\sqrt{x-1}\)
2. \(\dfrac{1}{2}\sqrt{x+1}-\dfrac{3}{2}\sqrt{9x+9}+24\sqrt{\dfrac{x+1}{64}}=-17\)
3. \(-5x+7\sqrt{x}+12=0\)
Em cảm ơn ạ
Giải phương trình :
a/ \(\dfrac{1}{2}\).\(\sqrt{x-1}\) - \(\dfrac{3}{2}\) . \(\sqrt{9x-9}\) +24 . \(\sqrt{\dfrac{x-1}{64}}\)=-17
b/3x - 7\(\sqrt{x}\) +4 =0
c/ -5x +7\(\sqrt{x}\) +12 =0
Tính:
a, A= \(\sqrt{\dfrac{3+\sqrt{5}}{3-\sqrt{5}}}\)+ \(\sqrt{\dfrac{3-\sqrt{5}}{3+\sqrt{5}}}\)
b, B= \(\dfrac{3+\sqrt{5}}{2\sqrt{2}+\sqrt{3+\sqrt{5}}}\)+ \(\dfrac{3-\sqrt{5}}{2\sqrt{2}-\sqrt{3-\sqrt{5}}}\)
c, C= \(\dfrac{1}{2\sqrt{1}+1\sqrt{2}}+\dfrac{1}{3\sqrt{2}+2\sqrt{3}}+...+\dfrac{1}{25\sqrt{24}+24\sqrt{25}}\)
Rút gọn :
\(B=\dfrac{1}{\sqrt{1}-\sqrt{2}}+\dfrac{1}{\sqrt{2}-\sqrt{3}}+\dfrac{1}{\sqrt{3}-\sqrt{4}}+...+\dfrac{1}{\sqrt{24}-\sqrt{25}}\)
1.Chứng minh:
\(\frac{\left(5\sqrt{3}+\sqrt{50}\right)\left(5-\sqrt{24}\right)}{\sqrt{75}-5\sqrt{2}}=1\)
(5-\(\dfrac{7-\sqrt{7}}{1-\sqrt{7}}\))(\(\dfrac{\sqrt{14}+\sqrt{7}}{1+\sqrt{2}}\)-5)
Rút gọn
1, \(2\sqrt{5}-\sqrt{125}-\sqrt{80}\)
2, \(3\sqrt{2}-\sqrt{8}+\sqrt{50}-4\sqrt{32}\)
3, \(\sqrt{18}-3\sqrt{80}-2\sqrt{50}+2\sqrt{45}\)
4, \(\sqrt{27}-2\sqrt{3}+2\sqrt{48}-3\sqrt{75}\)
5, \(3\sqrt{2}-4\sqrt{18}+\sqrt{32}-\sqrt{50}\)
6, \(2\sqrt{3}-\sqrt{75}+2\sqrt{12}-\sqrt{147}\)
7, \(\sqrt{20}-2\sqrt{45}-3\sqrt{80}+\sqrt{125}\)
8, \(6\sqrt{12}-\sqrt{20}-2\sqrt{27}+\sqrt{125}\)
9, \(4\sqrt{24}-2\sqrt{54}+3\sqrt{6}-\sqrt{150}\)
10, \(2\sqrt{18}-3\sqrt{80}-5\sqrt{147}+5\sqrt{245}-3\sqrt{98}\)
Các bạn ơi !! giúp mik với đi !!!!!
chứng minh :a) 11+6\(\sqrt{2}\)= (3+\(\sqrt{2}\))\(^2\)
b) \(\sqrt{11+6\sqrt{2}}+\sqrt{11-6\sqrt{2}}\)=6
c) \(\sqrt{8-2\sqrt{7}}-\sqrt{8+2\sqrt{7}}\)= -2
d) \(\sqrt{49-12\sqrt{5}}-\sqrt{49+12\sqrt{5}}\)=-4