Ta có : \(x\sqrt{x}-x-2\sqrt{x}=0\)
=> \(\sqrt{x}\left(x-\sqrt{x}-2\right)=0\)
=> \(\left[{}\begin{matrix}\sqrt{x}=0\\x-\sqrt{x}-2=0\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}x=0\\\left(\sqrt{x}\right)^2-\sqrt{x}-2=0\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}x=0\\\sqrt{x}=2\\\sqrt{x}=-1\left(VL\right)\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)
Vậy ....
( ĐKXĐ tự tìm hen )