Các câu hỏi tương tự
cho 12-x / 27-y =12 /27 . so sanh x/y va 12/27
a) Tìm số nguyên x, biết:
\(\frac{x}{9}=\frac{-12}{27}\)
b) Tìm số nguyên x, biết: 12 - ( x - 4 ) = 17
c) Tìm y biết: \(\left(1\frac{2}{3}+2\frac{2}{3}y\right).\frac{10}{11}=2\frac{3}{11}\)
So sanh
\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)Va \(\frac{4}{35}+\frac{4}{63}+\frac{4}{99}+\frac{4}{143}+\frac{4}{195}\)
tìm x
\(\frac{x}{15}\)+\(\frac{27-x}{5}\)=\(\frac{x}{4}\)+\(\frac{27-x}{12}\)
giúp mình vs mn ....
câu 3 ta có frac{x}{-3}y/5 xfrac{-3y}{5}thay x -3y/5 vào xy-5/27 ta được-frac{-3y}{5}*y-5/27frac{-3y^{^2}}{5}-5/27.-3y^2 -5/27 :5-5/27*1/5 -3y^2-1/27y^2 -1/27 :(-3)-1/27*(-1/3)1/81y1/9Khi đó x -5/27 : 1/9 -5/27 *9 -5/3vậy x -5/3 ,y 1/9
Đọc tiếp
câu 3
ta có \(\frac{x}{-3}\)=y/5 => x=\(\frac{-3y}{5}\)
thay x= -3y/5 vào xy=-5/27 ta được
-\(\frac{-3y}{5}\)*y=-5/27
=>\(\frac{-3y^{^2}}{5}\)=-5/27
=>.-3y^2 =-5/27 :5=-5/27*1/5
=> -3y^2=-1/27
=>y^2 =-1/27 :(-3)=-1/27*(-1/3)=1/81
=>y=1/9
Khi đó x= -5/27 : 1/9 = -5/27 *9 = -5/3
vậy x= -5/3 ,y = 1/9
A = \(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)va B = \(\frac{4}{35}+\frac{4}{63}+\frac{4}{99}+\frac{4}{143}+\frac{4}{195}\)
So sánh
\(\left(\frac{2}{199}-\frac{3}{398}\right):\frac{17}{199}+\frac{3}{17}\)
\(\left(\frac{-1}{6}+\frac{5}{-12}\right)+\frac{7}{12}\)
\(0.6\times\frac{8}{5}\times30\times0.675\times1\frac{2}{9}\)
\(\frac{43}{27}\left(\frac{27}{43}+\frac{86}{54}\right)-\frac{86}{54}\left(\frac{43}{27}-\frac{27}{43}\right)\)
So sanh
\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)va\(\frac{4}{35}\)+\(\frac{4}{63}\)+\(\frac{4}{99}\)+\(\frac{4}{143}\)+\(\frac{4}{195}\)
Tim cac so x,y,z,t biet:
\(\frac{27}{4}=\frac{-x}{3}=\frac{3}{y^2}=\frac{\left(z+3\right)^3}{-4}=\frac{\left|t\right|-2}{8}\)
Trinh bai cach lanm ra he