\(y\times\left(y+1\right)=2+4+6+....+20+22.\)
\(\Leftrightarrow y\times\left(y+1\right)=\left[\left(22-2\right):2+1\right]\times\left[\left(22+2\right):2\right]\)
\(\Leftrightarrow y\times\left(y+1\right)=11\times12\)
\(\Leftrightarrow y\times\left(y+1\right)=11\times\left(11+1\right)\)
Vậy y=11