Đặt z -60 = t
\(x+y+z=100\Rightarrow x+y+t=40;\)
\(\Leftrightarrow x+y+t\ge3\sqrt[3]{xyt}\Leftrightarrow xyt\le\frac{\left(x+y+t\right)^3}{3^3}=\left(\frac{40}{3}\right)^3\)
\(Max\left(xyt\right)=\left(\frac{40}{3}\right)^3\) khi x =y =t =40/3 => z =60+t =60+40/3=220/3
=>\(xyz\le\frac{40}{3}.\frac{40}{3}.\frac{220}{3}=\frac{352000}{27}\) khi x =y =40/3 ; z =220/3