Ta co x+x:3=24 =>2x:3=24=>2x=24.3=>2x=72=>x=72:2=35
ta có:
c1: \(x+\frac{x}{3}=24\)
\(\Rightarrow\frac{x}{3}=24-x\)(chuyển vế đổi dấu)
\(\Rightarrow x=72-3x\)
\(\Leftrightarrow4x=72\)
\(\Leftrightarrow x=18\)
c2 :
\(x+\frac{x}{3}=24\)
\(\Rightarrow\frac{3x+x}{3}=24\)
\(\Rightarrow\frac{4x}{3}=24\)
\(\Leftrightarrow4x=24.3\)
\(\Leftrightarrow4x=72\)
\(\Rightarrow x=18\)