x + [x + 1] + [x + 2]+...+[x + 100] = 500000
=> x + x + x + ..... + x + (1 + 2 + 3 + ..... + 100) = 500 000
=> 100x + 5050 = 500 000
=> 100x = 500 000 - 5050
=> 100x = 494950
=> x = 494950 : 100
=> x = 4949,5
x + [x + 1] + [x + 2]+...+[x + 100] = 500000
=> x + x + x + ..... + x + (1 + 2 + 3 + ..... + 100) = 500 000
=> 100x + 5050 = 500 000
=> 100x = 500 000 - 5050
=> 100x = 494950
=> x = 494950 : 100
=> x = 4949,5
Tìm x biết:1+2+3+...+x=500000
Bài 6 Tìm x
1) ( x+1 ) + ( x+2 ) + ( x+3 ) + ... + ( x+100 ) = 5750
2) ( 2x-1 ) + ( 4x-2 ) + ... + ( 200x - 100 ) = 5050
3) ( x+2 ) + ( x+4 ) + ( x+6 ) + ... + ( x + 100) = 2650
( 100-1 ) x X + ( 100-2 ) x X + X + 2 x X = ?????????????????????
1 x 100 + 2 x 99 + 3 x 98 + .....+ 99 x 2 + 100 x 1 = ?
1/Tìm x,biết:
a)x+(x+1)+(x+2)+(x+3)+...+(x+99)+(x+100)=5555
b)1+2+3+4+...+x=820
c)3(x+1)=9.27
d)x+2x+3x+...+99x+100x=15150
e)(x+1)+(x+2)+(x+3)+...+(x+100)=205550
f)3x+3x+1+3x+2=351
1 x 2 + 2 x 3 + 3 x 4 + ... + 100 x 101 =
1 x 2 x 3 + 2 x 3 x 4 + ... + 100 x 101 x 102
Có cả lời giải nhé
bài 1 tìm x
x+a=a
x+a>a
x+a<a
x*(x+1)=12
x*(x+1)*(x+2)=120
bài 2 tính a = ( 100 -1)*(100-2).......(100-n) với n thuộc n*, tích có 100 thừa số
tìm x thuộc Z
a)1+2+3+.........+x=5050
b)1/2+1/6+........1x2+x=99/100
c)1/6+1/12+.......1/x2-x=59/100
d)x-2017+x-2016+.........+99+100=0
g)x-1+x-2+x-3+.......x-2017=0
(10 X 20 X 30 X ... X 100)+(1 + 2 + 3 + ... + 100)-(-1 + -2 + -3 + ... + -25) = x (xϵZ)