x(x-1)=1-x2
x2-x=1-x2
2x2-x-1=0
\(\hept{\begin{cases}x=1\\x=\frac{-1}{2}\end{cases}}\)
x(x-1)= (1-x)(1+x)
x(x-1)+(x-1)(x+1)=0
(x-1) (x + x+1)= 0
(x-1)(2x+1)=0
x=1 hoặc x = -1/2
\(x\left(x-1\right)=1-x^2\)
\(x^2-x=1-x^2\)
\(x^2-x-1+x^2=0\)
\(2x^2-x-1=0\)
\(2x^2-2x+x-1=0\)
\(2x\left(x-1\right)+\left(x-1\right)=0\)
\(\left(2x+1\right)\left(x-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=0\\x-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=1\end{cases}}}\)
