Ta có: \(\frac{5}{6}=\frac{10}{12}\)
\(\frac{1}{2}=\frac{6}{12}\)
\(1=\frac{12}{12}\)
\(\frac{4}{3}=\frac{16}{12}\)
Mà \(\frac{6}{12}<\frac{10}{12}<\frac{12}{12}<\frac{16}{12}\)
=> \(\frac{1}{2}<\frac{5}{6}<1<\frac{4}{3}\)
\(\frac{1}{2}=\frac{3}{6}\) , \(1=\frac{6}{6}\) , \(\frac{4}{3}=\frac{8}{6}\)
\(\frac{3}{6}< \frac{5}{6}< \frac{6}{6}< \frac{8}{6}\)
Nên \(\frac{1}{2}< \frac{5}{6}< 1< \frac{4}{3}\)
Vậy thứ tự từ bé đến lớn là \(\frac{1}{2},\frac{5}{6},1,\frac{4}{3}\)