(x+7).(x-5)=0
\(< =>\left[{}\begin{matrix}x+7=0\\x-5=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=0-7\\x=0+5\end{matrix}\right.\)
\(< =>\left[{}\begin{matrix}x=-7\\x=5\end{matrix}\right.\)
Vậy x=-7 hoặc x=5
1, 72-3./x+1/=9
2, 17-(43-/x/)=45
3, 3/x-1/-5=7
4, -12.(x-5)+7.(3-x)=5
5, (x-2) . (x+4)=0
6, (x-2).(x+15)=0
7, (7-x).(x+19)=0
8, -5<x<1
9, /x/<3
10, (x.3).(x-5)<0
Tìm x thuộc Z biết
a,-12.(x-5)+7.(3-x)=5
b,-15(x-2)+7.(3-x)=7
c,(x-3).(x-5)<0
d,(x-5).(x-7)>0
Tìm x :
1) -12 + 3 . ( -x +7 ) = -18
2) x . ( x + 7 ) = 0
3) ( -x + 5 ) . ( 3 - x ) = 0
4) ( x + 12 ) . ( x - 3 ) = 0
5) x . ( 2 + x ) . ( 7 - x ) = 0
6) ( x - 1 ) . ( x + 2 ) . ( -x - 3 ) = 0
Bài 1: Tìm x
1/(2.x-5)+17=6
2/10-2.(4-3x)=-4
3/-12+3.(-x+7)=-18
4/24:(3.x-2)=-3
5/-45:5.(-3-2.x)=3
6/x.(x+7)=0
7/(x+12).(x-3)=0
8/(-x+5).(3-x)=0
9/x.(2+x).(7-x)=0
10/(x-1).(x+2).(-x-3)=0
Tìm x
1. x(x+7)=0
2. (x+12)(x-3)=0
3. (-x+5)(3-x)=0
4. x(2+x)(7-x)=0
5. (x-1)(x+2)(-x-3)=0
tìm x
1/ x.(x+7)=0
2/ (x+12).(x-3)=0
3/ (-x+5).(3-x)=0
4/ x.(2+x).(7-x)=0
5/ (x-1).(x+2).(-x-3)=0
Tìm x:
a) x.x+7)=0
b) (x+12).(x-3)=0
c) (-5+5).(3-x)=0
d)x.(2+x).(7-x)=0
e) (x-1).(x-2).(-x-3)=0
1) -12 (x-5) +7(3-x)=5
2) (x-2). (x+4)=0
3) ( x-2) .( x+15) =0
4) (7-x) .(x+19)=0
5)-5,x,1
6) / x/<3
7)(x-3) (x-5)<0
8)2x2-3=29
Các bạn giải giúp mình nhé.BuingBuing
(x+7)(x-9)=0
/2x-5/-7=22
(x-2)(5-x)=0
a ) | x - 2| = 3
b) -3 | x + 1 | = 9
c) 3 | x - 1 | -5 = 7
d) -12 ( x - 5 ) + 7 ( 3 - x ) = 5
e) ( x - 2 ) . ( x + 15 ) = 0
f) (7 - x ) . ( x + 19 ) = 0
g) ( x - 3 ) (x - 5 ) < 0
h) -6x - (- 7 ) = 25
i) 46 - ( x - 11 ) = -48
