Question

(-x³y²z)⁴:(-xy²z)³

Answer 1

\(\frac{\left(-x^3y^2z\right)^4}{\left(-xy^2z\right)^3}=\frac{x^{12}y^8z^4}{-x^3y^6z^3}=-x^9y^2z\)

Answer 2

\(\left(-x^3y^2z\right)^4:\left(-xy^2z\right)^3\)

\(=\left(-x^{12}y^8z^4\right):\left(-x^3y^6z^3\right)\)

\(=x^9y^2z.\)

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