\(x\left(3x-2\right)-5\left(2-3x\right)=0\)
\(\Leftrightarrow\left(x+5\right)\left(3x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+5=0\\3x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=\dfrac{2}{3}\end{matrix}\right.\)
Vậy...
x(3x-2)-5(2-3x) =0
-\(\left[x\left(3x-2\right)\right]\) - 5(2-3x)=0
-x(2-3x)-5(2-3x)=0
(2-3x)*(-x-5)=0
\(\left[{}\begin{matrix}2-3x=0\\\left(-x-5\right)=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}3x=2\\-x=5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=5\end{matrix}\right.\)
