Question

tìm x

x(2x - 7)-3(7-2x) = 0

(3x -5)^2 - (2x - 3)^2 = 0

Answer 1

\(x\left(2x-7\right)-3\left(7-2x\right)=0\)

\(\Rightarrow x\left(2x-7\right)+3\left(2x-7\right)=0\)

\(\Rightarrow\left(x+3\right)\left(2x-7\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x+3=0\\2x-7=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=\dfrac{7}{2}\end{matrix}\right.\)

\(\left(3x-5\right)^2-\left(2x-3\right)^2=0\)

\(\Rightarrow\left(3x-5+2x-3\right)\left(3x-5-2x+3\right)=0\)

\(\Rightarrow\left(5x-8\right)\left(x-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}5x-8=0\\x-2=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{8}{5}\\x=2\end{matrix}\right.\)