x/3=y/2
=> 2x/6=5y/10=2x+5y/6+10=32/16=2
+, x/3=2 => x=6
+, y/2=2 => y=4
Vậy ....
Ta có : \(\frac{x}{3}=\frac{y}{2}\Leftrightarrow2x=3y\Rightarrow x=\frac{3y}{2}\)
Thay \(x=\frac{3y}{2}\)vào biểu thức \(2x+5y=32\);ta được: \(\frac{3y.2}{2}+5y=32\)
\(\Leftrightarrow\frac{6y}{2}+5y=32\Leftrightarrow3y+5y=32\Leftrightarrow8y=32\Leftrightarrow y=4\)
\(\Rightarrow x=\frac{3.4}{2}=6\)
Vậy x ; y = {6 ; 4}