Question

x^3-3x^2+2x=0

Answer 1

x = 2

Answer 2

\(\Leftrightarrow x\left(x^2-3x+2\right)=0\)

\(\Leftrightarrow x\left(x-1\right)\left(x-2\right)=0\)

hay \(x\in\left\{0;1;2\right\}\)

Answer 3

x = 2

Answer 4

⇔ x ( \(x^2\) − 3 x + 2 ) = 0

⇔ x ( x − 1 ) ( x − 2 ) = 0

hay x ∈ { 0 ; 1 ; 2 }