Question

(x+2)(x+4)(x+6)(x+8)+16

Answer 1

Ta có:

\(\left(x+2\right)\left(x+8\right)\left(x+4\right)\left(x+6\right)+16\)

\(=\left(x^2+10x+16\right)\left(x^2+10x+24\right)+16\)

Đặt x² + 10x + 16= t thì:

\(t\left(t+8\right)+16=t^2+8t+16\)

\(=t^2+4t+4t+16=\left(t+4\right)^2\)

\(=\left(x^2+10+20\right)^2\)

Answer 2

https://hoc24.vn/hoi-dap/question/172677.html

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