[( x + 2 )( x - 5 )]2016 = 0
=> ( x + 2 )( x - 5 ) = 0
=> x + 2 = 0 hoặc x - 5 = 0
+) x + 2 = 0 => x = -2
+) x - 5 = 0 => x = 5
Vậy x = -2 hoặc x = 5
\(\orbr{\begin{cases}x+2=0\\x-5=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-2\\x=5\end{cases}}}\)
\(\left|\left(x+2\right)\left(x-5\right)\right|^{2016}=0\)
\(\Rightarrow\left(x+2\right)\left(x+5\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+2=0\\x-5=0\end{cases}}\)
TH1:
\(x+2=0\)
\(x=-2\)
TH2:
\(x-5=0\)
\(x=5\)
\(\Leftrightarrow\orbr{\begin{cases}x=-2\\x=5\end{cases}}\)
\(\left|\left(x+2\right)\left(x-5\right)\right|^{2016}=0\)
\(\Rightarrow\left(x+2\right)\left(x-5\right)=0\)
\(\Rightarrow\hept{\begin{cases}x+2=0\\x-5=0\end{cases}\Rightarrow}\hept{\begin{cases}x=-2\\x=5\end{cases}}\)