\(\left|x+2\right|+\left|x+5\right|=0\)
\(\Rightarrow\orbr{\begin{cases}x+2=0\\y+5=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2\\y=5\end{cases}}\)
Ta có:\(\hept{\begin{cases}\left|x+2\right|\ge0\\\left|y+5\right|\ge0\end{cases}\Rightarrow\left|x+2\right|+\left|y+5\right|\ge0}\)
Dấu "=" xảy ra khi \(\hept{\begin{cases}\left|x+2\right|=0\\\left|y+5\right|=0\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x+2=0\\y+5=0\end{cases}\Rightarrow\hept{\begin{cases}x=-2\\y=-5\end{cases}}}\)
Vì \(\left|x+2\right|+\left|y+5\right|=0\)
\(\Rightarrow\orbr{\begin{cases}x+2=0\\y+5=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-2\\y=-5\end{cases}}\)
Vậy \(x=-2;y=-5\)
Ủng hộ mk nha !!!
\(x+2=y+5\)
=>\(x+2=0=>x=-2\)
=> \(y+5=0=>y=-5\)
