a)x2 +x =0
x(x+1)=0
* x=0
* x+1=0
x=0-1
x=-1
Vậy x=0 hoặc x=-1
2.(x-1) +3(x-2) =x-4
2x-2+3x-6=x-4
x+3x-x=-4+2+6
3x=4
x=\(\frac{4}{3}\)
a,
x2 +x =0
\(\orbr{\begin{cases}x^2=0\\x=0\end{cases}}\)
Vậy x= 0
b,2.(x-1) +3(x-2) =x-4
2x - 2 + 3x - 6 = x - 4
2x + 3x - x = -4 +6 + 2
4x = 0
Vậy x = 0