Question

\(x^2-\left(x-1\right)^2+2\left(x-1\right)-1\) Phân tích đa thức thành nhân tử

Answer 1

\(x^2-\left(x-1\right)^2+2\left(x-1\right)-1\)

\(=x^2-\left(\left(x-1\right)^2-2\left(x-1\right)+1^2\right)\)

\(=x^2-\left(x-1-1\right)^2\)

\(=\left(x-x+2\right)\left(x+x-2\right)=2\left(2x-2\right)=4.\left(x-1\right)\)

Answer 2

= (x²-1) - (x-1)² + 2(x-1)

= (x-1)(x+1) - (x-1)² + 2(x-1)

= (x-1)[x+1-(x-1)+2]

= (x-1)(x+1-x+1+2)

= 4(x-1)

tick nha

Answer 3

\(x^2-\left(x-1\right)^2+2\left(x-1\right)-1\)

\(=x^2-x^2+2x-1+2x-2-1\)

\(=4x-4=4\left(x-1\right)\)