Question

x^2 + 6x + 5

x^2 - 7x + 12

x^2 -7x + 10

Answer 1

\(x^2+6x+5=x^2+5x+x+5=x\left(x+5\right)+\left(x+5\right)=\left(x+1\right)\left(x+5\right)\) 

\(x^2-7x+12=x^2-4x-3x+12=x\left(x-4\right)-3\left(x-4\right)=\left(x-3\right)\left(x-4\right)\) 

\(x^2-7x+10=x^2-2x-5x+10=x\left(x-2\right)-5\left(x-2\right)=\left(x-2\right)\left(x-5\right)\)

Answer 2

\(a,x^2+6x+5=x^2+5x+x+5\)

\(=x\left(x+5\right)+\left(x+5\right)=\left(x+5\right)\left(x+1\right)\)

\(b,\)\(x^2-7x+12=x^2-3x-4x+12\)

\(=x\left(x-3\right)-4\left(x-3\right)=\left(x-3\right)\left(x-4\right)\)

\(c,\)\(x^2-7x+10=x^2-2x-5x+10\)

\(=x\left(x-2\right)-5\left(x-2\right)=\left(x-2\right)\left(x-5\right)\)

Answer 3

a) \(x^2+6x+5=x^2+5x+x+5\) 

 \(=x\left(x+5\right)+\left(x+5\right)=\left(x+1\right)\left(x+5\right)\) 

b)\(x^2-7x+12=x^2-4x-3x+12=x\left(x-4\right)-3\left(x-4\right)=\left(x-3\right)\left(x-4\right)\) 

c)\(x^2-7x+10=x^2-2x-5x+10=x\left(x-2\right)-5\left(x-2\right)\)

  \(=\left(x-5\right)\left(x-2\right)\) 

hc tốt